# What Is Least Unit Cost And Example?

Nowadays, manufacturing businesses calculate the quantity of every material required for production and when it is needed using a technique called “Material Requirements Planning.”

The order’s size must be determined by the material planner, who is also responsible for placing it. Placing many orders each month might be highly expensive, not to mention the costs associated with keeping inventory on hand.

They should decide how best to balance the costs in order to come up with a viable financial solution.

The “lot sizing” optimization problem is thus named.

In this article, we will discuss one technique of lot sizing: the **least unit cost** technique and example to help you have a better understanding.

**Contents**show

**What does the least unit cost mean?**

The Least Unit Cost or LUC approach is a dynamic lot-sizing sizing strategy that determines the order quantity by identifying whether or not the demand for the following “n” periods, where “n” reduces the average cost per unit, will be met.

LUC is used to take the advantage of economic purchase discounts and also to meet the variations in the product demand

**Least Unit Cost example **

The Least Unit Cost approach seeks to reduce the average cost per unit. One piece of machinery, raw material, or component is referred to as a unit.

When “n” is chosen to minimize the average cost per unit, we determine the order quantity that will span the following “n” periods.

The Least Unit Cost approach is a dynamic lot-sizing technique that multiplies each test lot size’s ordering and inventories carrying costs by the quantity of units in every lot size, then chooses the test lot size with the smallest unit cost.

In this example, we’ll apply a new table to this technique’s computation of the best lot size.

Cumulative order quantity: the total amount to be ordered per week

Excessive inventory is that which is not required now but will be in the future.

Week carried: The total number of weeks that the extra inventory is carried.

- Carrying cost/week/unit = 0,17*25€*52 weeks = 0,08173
- Carrying cost in week 6 = 120*0.08173*3 = 29.4*
- Unit cost = Total cost/Cumulative Order Quantity

Since the cost per unit would be 0.27 euros each week in the instance below, the LUT technique would advise ordering 630 units, which would satisfy the anticipated demand until week 6.

After the week 6, when we have a better understanding of the anticipated demand for the following few weeks, we re-start the process.

Order price: 200 Euros

Inventory costs: 186.2€ plus (unknown for the previous two periods)

Costs of purchases: (630 +?)*25€ = ?

Entire cost: To estimate the total cost, we need to know the requirements for the upcoming time periods.

**Solution with least unit cost **

We should execute the following example, also adhering to the presentation and formulas in Silver et al (1998) and Nahmias (2013)

Cost if only the necessary quantity is ordered during Period 1:

A+ht=11(t-1)Xt/t=11Xt=A/Xt=200/100=2MU/unit

Cost for obtaining the following required amount in period 2 as well:

A+ht=12(t-1)Xt/t=12Xt=(200+0.2(0+1100)/(100+100)=1.10MU/unit

Cost for ordering period 3’s zero requested quantity as well:

A+ht=13(t-1)Xt/t=13Xt=(200+0.2(1100+20)/(100+100+0)=1.10MU/unit. The preceding Least Unit Cost is unaffected by a zero demand, hence the search goes on.

A+ht=14(t-1)Xt/t=14Xt=A+hi=13(ti–t1)Xi, ti/t=13Xi, ti

=(200+0.2(1100+(4-1)200)/(100+100+200)=0.85MU/unit

Cost for ordering the third quantity that was requested after period 6:

A+hi=14(ti–t1)Xi, ti/t=14Xi, ti= (200 + 0.2(700 + (6 -1)100)/(400 +100)

=0.88 MU/unit

0.88 > 0.85; therefore Q1=t=14Xt=t=13Xi, ti= 100 +100+ 200 = 400 units

Therefore, starting in period 5 makes no sense in order to compute the required order quantity for the subsequent order quantity, which we start in period 6 instead.

X6=X4,t4=6=100 units

Cost for ordering the quantity in the period 6: A/X4,t4=200/100=2 MU/ unit

Cost of ordering the additional quantity in period 8 in addition to the quantity required in period 6:

A+hi=55(ti–t4)Xi, ti/t=45Xi, ti=(200+0.22350/(100+350)=0.76MU/unit

Therefore, Q2=t=69Xt=t=45Xi, ti= 100 +350=450 units

This response provides the entire cost of setup and inventory holding:

200 + 0.2(1100 + (4 -1)200) + 200 + 0.2(8 – 6)350)= 680 MU

**Conclusion**

To make finished goods, manufacturing companies need to buy a lot of raw materials and base components, the majority of which are supplied by outside vendors.

The least unit cost technique is the way to optimize the balance between the costs to find a viable financial solution.

We hope this post has already been useful for you. Feel free to ask us if you still have questions about the least unit cost.